2513409117 has 4 divisors (see below), whose sum is σ = 3351212160. Its totient is φ = 1675606076.

The previous prime is 2513409113. The next prime is 2513409131. The reversal of 2513409117 is 7119043152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2513409117 - 2² = 2513409113 is a prime.

It is a super-3 number, since 3×2513409117³ (a number of 29 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2513409113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 418901517 + ... + 418901522.

It is an arithmetic number, because the mean of its divisors is an integer number (837803040).

Almost surely, 2^2513409117 is an apocalyptic number.

It is an amenable number.

2513409117 is a deficient number, since it is larger than the sum of its proper divisors (837803043).

2513409117 is an equidigital number, since it uses as much as digits as its factorization.

2513409117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 837803042.

The product of its (nonzero) digits is 7560, while the sum is 33.

The square root of 2513409117 is about 50133.9118461745. The cubic root of 2513409117 is about 1359.6310123902.

The spelling of 2513409117 in words is "two billion, five hundred thirteen million, four hundred nine thousand, one hundred seventeen".