Base | Representation |
---|---|
bin | 100100100100110011001… |
… | …001100011010011000011 |
3 | 22220021120010212212200200 |
4 | 210210303021203103003 |
5 | 312134432441310201 |
6 | 5202351345020243 |
7 | 346405512404430 |
oct | 44446311432303 |
9 | 8807503785620 |
10 | 2513414010051 |
11 | 889a297585aa |
12 | 347149324683 |
13 | 15302478c2a9 |
14 | 8991540cb87 |
15 | 455a6592386 |
hex | 249332634c3 |
2513414010051 has 24 divisors (see below), whose sum is σ = 4149483702624. Its totient is φ = 1436113411200.
The previous prime is 2513414010017. The next prime is 2513414010071. The reversal of 2513414010051 is 1500104143152.
2513414010051 is a `hidden beast` number, since 2 + 513 + 4 + 1 + 40 + 100 + 5 + 1 = 666.
It is not a de Polignac number, because 2513414010051 - 29 = 2513414009539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2513414009997 and 2513414010024.
It is not an unprimeable number, because it can be changed into a prime (2513414010071) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 967626 + ... + 2441951.
It is an arithmetic number, because the mean of its divisors is an integer number (172895154276).
Almost surely, 22513414010051 is an apocalyptic number.
2513414010051 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2513414010051 is a deficient number, since it is larger than the sum of its proper divisors (1636069692573).
2513414010051 is a wasteful number, since it uses less digits than its factorization.
2513414010051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3421291 (or 3421288 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
The spelling of 2513414010051 in words is "two trillion, five hundred thirteen billion, four hundred fourteen million, ten thousand, fifty-one".
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