Base | Representation |
---|---|
bin | 1011011011100010100111… |
… | …10001111010111001010101 |
3 | 10021222221020222202001101120 |
4 | 11231301103301322321111 |
5 | 11243310103334231123 |
6 | 125243040355514153 |
7 | 5202661315410432 |
oct | 555612361727125 |
9 | 107887228661346 |
10 | 25135554211413 |
11 | 8010a24084998 |
12 | 299b5322b8959 |
13 | 1104370b64749 |
14 | 62c7d29d8b89 |
15 | 2d8c77d482e3 |
hex | 16dc53c7ae55 |
25135554211413 has 4 divisors (see below), whose sum is σ = 33514072281888. Its totient is φ = 16757036140940.
The previous prime is 25135554211403. The next prime is 25135554211433. The reversal of 25135554211413 is 31411245553152.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25135554211413 - 212 = 25135554207317 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25135554211403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4189259035233 + ... + 4189259035238.
It is an arithmetic number, because the mean of its divisors is an integer number (8378518070472).
Almost surely, 225135554211413 is an apocalyptic number.
It is an amenable number.
25135554211413 is a deficient number, since it is larger than the sum of its proper divisors (8378518070475).
25135554211413 is an equidigital number, since it uses as much as digits as its factorization.
25135554211413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8378518070474.
The product of its digits is 360000, while the sum is 42.
Adding to 25135554211413 its reverse (31411245553152), we get a palindrome (56546799764565).
The spelling of 25135554211413 in words is "twenty-five trillion, one hundred thirty-five billion, five hundred fifty-four million, two hundred eleven thousand, four hundred thirteen".
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