Base | Representation |
---|---|
bin | 1011011011100011111001… |
… | …10010100000011111011101 |
3 | 10022000000000221101002012011 |
4 | 11231301330302200133131 |
5 | 11243313011002400021 |
6 | 125243232534311221 |
7 | 5203014341444260 |
oct | 555617462403735 |
9 | 108000027332164 |
10 | 25136242231261 |
11 | 8011247491437 |
12 | 299b6a47b8511 |
13 | 110445056ab95 |
14 | 62c85a134cd7 |
15 | 2d8cb8450de1 |
hex | 16dc7cca07dd |
25136242231261 has 4 divisors (see below), whose sum is σ = 28727133978592. Its totient is φ = 21545350483932.
The previous prime is 25136242231231. The next prime is 25136242231273. The reversal of 25136242231261 is 16213224263152.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25136242231261 - 213 = 25136242223069 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25136242231231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1795445873655 + ... + 1795445873668.
It is an arithmetic number, because the mean of its divisors is an integer number (7181783494648).
Almost surely, 225136242231261 is an apocalyptic number.
It is an amenable number.
25136242231261 is a deficient number, since it is larger than the sum of its proper divisors (3590891747331).
25136242231261 is an equidigital number, since it uses as much as digits as its factorization.
25136242231261 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3590891747330.
The product of its digits is 207360, while the sum is 40.
The spelling of 25136242231261 in words is "twenty-five trillion, one hundred thirty-six billion, two hundred forty-two million, two hundred thirty-one thousand, two hundred sixty-one".
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