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25140053 = 86329131
BaseRepresentation
bin101111111100…
…1101101010101
31202022020200002
41133321231111
522413440203
62254501045
7423454421
oct137715525
952266602
1025140053
1113211104
128504785
135292b93
1434a5b81
152318d88
hex17f9b55

25140053 has 4 divisors (see below), whose sum is σ = 25170048. Its totient is φ = 25110060.

The previous prime is 25140047. The next prime is 25140061. The reversal of 25140053 is 35004152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25140053 - 28 = 25139797 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25140043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13703 + ... + 15428.

It is an arithmetic number, because the mean of its divisors is an integer number (6292512).

Almost surely, 225140053 is an apocalyptic number.

It is an amenable number.

25140053 is a deficient number, since it is larger than the sum of its proper divisors (29995).

25140053 is an equidigital number, since it uses as much as digits as its factorization.

25140053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29994.

The product of its (nonzero) digits is 600, while the sum is 20.

The square root of 25140053 is about 5013.9857399079. The cubic root of 25140053 is about 292.9467806286.

It can be divided in two parts, 251 and 40053, that added together give a palindrome (40304).

The spelling of 25140053 in words is "twenty-five million, one hundred forty thousand, fifty-three".

Divisors: 1 863 29131 25140053