25140117309 has 4 divisors (see below), whose sum is σ = 33520156416. Its totient is φ = 16760078204.

The previous prime is 25140117287. The next prime is 25140117323. The reversal of 25140117309 is 90371104152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25140117309 - 2⁸ = 25140117053 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 25140117309.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25140117329) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4190019549 + ... + 4190019554.

It is an arithmetic number, because the mean of its divisors is an integer number (8380039104).

Almost surely, 2^25140117309 is an apocalyptic number.

It is an amenable number.

25140117309 is a deficient number, since it is larger than the sum of its proper divisors (8380039107).

25140117309 is an equidigital number, since it uses as much as digits as its factorization.

25140117309 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8380039106.

The product of its (nonzero) digits is 7560, while the sum is 33.

The spelling of 25140117309 in words is "twenty-five billion, one hundred forty million, one hundred seventeen thousand, three hundred nine".