Base | Representation |
---|---|
bin | 10111011010011101… |
… | …111101111011111001 |
3 | 2101220001120200202210 |
4 | 113122131331323321 |
5 | 402441333003213 |
6 | 15314344045333 |
7 | 1546665353223 |
oct | 273235757371 |
9 | 71801520683 |
10 | 25140125433 |
11 | a730a44375 |
12 | 4a57463849 |
13 | 24a8588987 |
14 | 1306c21413 |
15 | 9c21510c3 |
hex | 5da77def9 |
25140125433 has 16 divisors (see below), whose sum is σ = 35019374400. Its totient is φ = 16021924800.
The previous prime is 25140125429. The next prime is 25140125449. The reversal of 25140125433 is 33452104152.
It is not a de Polignac number, because 25140125433 - 22 = 25140125429 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 25140125433.
It is not an unprimeable number, because it can be changed into a prime (25140125033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1421743 + ... + 1439316.
It is an arithmetic number, because the mean of its divisors is an integer number (2188710900).
Almost surely, 225140125433 is an apocalyptic number.
It is an amenable number.
25140125433 is a deficient number, since it is larger than the sum of its proper divisors (9879248967).
25140125433 is a wasteful number, since it uses less digits than its factorization.
25140125433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2861192.
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 25140125433 its reverse (33452104152), we get a palindrome (58592229585).
The spelling of 25140125433 in words is "twenty-five billion, one hundred forty million, one hundred twenty-five thousand, four hundred thirty-three".
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