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25140420433 = 731489231289
BaseRepresentation
bin10111011010011111…
…000101111101010001
32101220002010200102201
4113122133011331101
5402441421423213
615314354243201
71550001022252
oct273237057521
971802120381
1025140420433
11a731125a77
124a57586501
1324a866002b
141306c9ab29
159c21ad6dd
hex5da7c5f51

25140420433 has 8 divisors (see below), whose sum is σ = 25502035400. Its totient is φ = 24779271168.

The previous prime is 25140420427. The next prime is 25140420499. The reversal of 25140420433 is 33402404152.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 154927809 + 24985492624 = 12447^2 + 158068^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 25140420433 - 221 = 25138323281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25140423433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6948 + ... + 224341.

It is an arithmetic number, because the mean of its divisors is an integer number (3187754425).

Almost surely, 225140420433 is an apocalyptic number.

It is an amenable number.

25140420433 is a deficient number, since it is larger than the sum of its proper divisors (361614967).

25140420433 is a wasteful number, since it uses less digits than its factorization.

25140420433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 232851.

The product of its (nonzero) digits is 11520, while the sum is 28.

Adding to 25140420433 its reverse (33402404152), we get a palindrome (58542824585).

The spelling of 25140420433 in words is "twenty-five billion, one hundred forty million, four hundred twenty thousand, four hundred thirty-three".

Divisors: 1 73 1489 108697 231289 16884097 344389321 25140420433