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2514152113 = 11228559283
BaseRepresentation
bin1001010111011010…
…1110101010110001
320111012211011022221
42111312232222301
520122110331423
61053251001041
7116205640354
oct22566565261
96435734287
102514152113
11108019a770
125a1b99181
13310b45b95
1419bc9629b
15eaac3e5d
hex95daeab1

2514152113 has 4 divisors (see below), whose sum is σ = 2742711408. Its totient is φ = 2285592820.

The previous prime is 2514152093. The next prime is 2514152171. The reversal of 2514152113 is 3112514152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2514152113 - 225 = 2480597681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2514152413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114279631 + ... + 114279652.

It is an arithmetic number, because the mean of its divisors is an integer number (685677852).

Almost surely, 22514152113 is an apocalyptic number.

It is an amenable number.

2514152113 is a deficient number, since it is larger than the sum of its proper divisors (228559295).

2514152113 is a wasteful number, since it uses less digits than its factorization.

2514152113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 228559294.

The product of its digits is 1200, while the sum is 25.

The square root of 2514152113 is about 50141.3214125835. The cubic root of 2514152113 is about 1359.7649739845.

Adding to 2514152113 its reverse (3112514152), we get a palindrome (5626666265).

The spelling of 2514152113 in words is "two billion, five hundred fourteen million, one hundred fifty-two thousand, one hundred thirteen".

Divisors: 1 11 228559283 2514152113