Base | Representation |
---|---|
bin | 100100100101101001110… |
… | …100000100010100001001 |
3 | 22220100221001121010220001 |
4 | 210211221310010110021 |
5 | 312143322232000001 |
6 | 5203022350003001 |
7 | 346440316635103 |
oct | 44455164042411 |
9 | 8810831533801 |
10 | 2514331125001 |
11 | 88a35a40a643 |
12 | 3473644a6461 |
13 | 15313c798b67 |
14 | 899a1142573 |
15 | 4560bd50001 |
hex | 24969d04509 |
2514331125001 has 16 divisors (see below), whose sum is σ = 2550381039360. Its totient is φ = 2478493416960.
The previous prime is 2514331124993. The next prime is 2514331125049. The reversal of 2514331125001 is 1005211334152.
It is a cyclic number.
It is not a de Polignac number, because 2514331125001 - 23 = 2514331124993 is a prime.
It is a super-2 number, since 2×25143311250012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2514331125701) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 102953970 + ... + 102978388.
It is an arithmetic number, because the mean of its divisors is an integer number (159398814960).
Almost surely, 22514331125001 is an apocalyptic number.
It is an amenable number.
2514331125001 is a deficient number, since it is larger than the sum of its proper divisors (36049914359).
2514331125001 is a wasteful number, since it uses less digits than its factorization.
2514331125001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28704.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 2514331125001 its reverse (1005211334152), we get a palindrome (3519542459153).
The spelling of 2514331125001 in words is "two trillion, five hundred fourteen billion, three hundred thirty-one million, one hundred twenty-five thousand, one".
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