25161160914137 has 4 divisors (see below), whose sum is σ = 25161965561856. Its totient is φ = 25160356266420.

The previous prime is 25161160914133. The next prime is 25161160914199. The reversal of 25161160914137 is 73141906116152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25161160914137 - 2² = 25161160914133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25161160914091 and 25161160914100.

It is not an unprimeable number, because it can be changed into a prime (25161160914133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 402276953 + ... + 402339494.

It is an arithmetic number, because the mean of its divisors is an integer number (6290491390464).

Almost surely, 2^{25161160914137} is an apocalyptic number.

It is an amenable number.

25161160914137 is a deficient number, since it is larger than the sum of its proper divisors (804647719).

25161160914137 is an equidigital number, since it uses as much as digits as its factorization.

25161160914137 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 804647718.

The product of its (nonzero) digits is 272160, while the sum is 47.

The spelling of 25161160914137 in words is "twenty-five trillion, one hundred sixty-one billion, one hundred sixty million, nine hundred fourteen thousand, one hundred thirty-seven".