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252001597 = 1129922303
BaseRepresentation
bin11110000010100…
…11110100111101
3122120012000012111
433001103310331
51004003022342
641001134021
76146656351
oct1701236475
9576160174
10252001597
1111a280591
127048a311
1340293793
142567b461
15171cc217
hexf053d3d

252001597 has 4 divisors (see below), whose sum is σ = 252035200. Its totient is φ = 251967996.

The previous prime is 252001577. The next prime is 252001601. The reversal of 252001597 is 795100252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 252001597 - 219 = 251477309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252001537) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 148 + ... + 22450.

It is an arithmetic number, because the mean of its divisors is an integer number (63008800).

Almost surely, 2252001597 is an apocalyptic number.

It is an amenable number.

252001597 is a deficient number, since it is larger than the sum of its proper divisors (33603).

252001597 is a wasteful number, since it uses less digits than its factorization.

252001597 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33602.

The product of its (nonzero) digits is 6300, while the sum is 31.

The square root of 252001597 is about 15874.5581670798. The cubic root of 252001597 is about 631.6372940520.

The spelling of 252001597 in words is "two hundred fifty-two million, one thousand, five hundred ninety-seven".

Divisors: 1 11299 22303 252001597