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2520034127005 = 5504006825401
BaseRepresentation
bin100100101010111101101…
…111010010110010011101
322220220122111210122220111
4210222331233102302131
5312242012214031010
65205404313050021
7350031536436103
oct44527557226235
98826574718814
102520034127005
1189181662743a
123484963b6911
1315383b178365
1489d8271dc73
154584286d58a
hex24abdbd2c9d

2520034127005 has 4 divisors (see below), whose sum is σ = 3024040952412. Its totient is φ = 2016027301600.

The previous prime is 2520034126969. The next prime is 2520034127011. The reversal of 2520034127005 is 5007214300252.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 741977227161 + 1778056899844 = 861381^2 + 1333438^2 .

It is not a de Polignac number, because 2520034127005 - 211 = 2520034124957 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252003412696 + ... + 252003412705.

It is an arithmetic number, because the mean of its divisors is an integer number (756010238103).

Almost surely, 22520034127005 is an apocalyptic number.

It is an amenable number.

2520034127005 is a deficient number, since it is larger than the sum of its proper divisors (504006825407).

2520034127005 is an equidigital number, since it uses as much as digits as its factorization.

2520034127005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 504006825406.

The product of its (nonzero) digits is 16800, while the sum is 31.

Adding to 2520034127005 its reverse (5007214300252), we get a palindrome (7527248427257).

The spelling of 2520034127005 in words is "two trillion, five hundred twenty billion, thirty-four million, one hundred twenty-seven thousand, five".

Divisors: 1 5 504006825401 2520034127005