Base | Representation |
---|---|
bin | 10111011110101101… |
… | …100010101010100101 |
3 | 2102002000112121002211 |
4 | 113132231202222211 |
5 | 403113044120101 |
6 | 15325410003421 |
7 | 1551521441431 |
oct | 273655425245 |
9 | 72060477084 |
10 | 25211316901 |
11 | a7681495a1 |
12 | 4a77276571 |
13 | 24ba2538c4 |
14 | 13124739c1 |
15 | 9c8514c51 |
hex | 5deb62aa5 |
25211316901 has 4 divisors (see below), whose sum is σ = 25456087072. Its totient is φ = 24966546732.
The previous prime is 25211316883. The next prime is 25211316917. The reversal of 25211316901 is 10961311252.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25211316901 - 229 = 24674445989 is a prime.
It is a super-2 number, since 2×252113169012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25211316001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122384931 + ... + 122385136.
It is an arithmetic number, because the mean of its divisors is an integer number (6364021768).
Almost surely, 225211316901 is an apocalyptic number.
It is an amenable number.
25211316901 is a deficient number, since it is larger than the sum of its proper divisors (244770171).
25211316901 is a wasteful number, since it uses less digits than its factorization.
25211316901 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 244770170.
The product of its (nonzero) digits is 3240, while the sum is 31.
The spelling of 25211316901 in words is "twenty-five billion, two hundred eleven million, three hundred sixteen thousand, nine hundred one".
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