Search a number
-
+
252133121131 = 3971039611257
BaseRepresentation
bin1110101011010001001…
…1100001110001101011
3220002210120221122012121
43222310103201301223
513112332034334011
6311454531452111
724134044111543
oct3526423416153
9802716848177
10252133121131
1197a24634781
1240a46a57037
131aa11ca5548
14c2bbc40323
15685a224e71
hex3ab44e1c6b

252133121131 has 8 divisors (see below), whose sum is σ = 253011911360. Its totient is φ = 251255556288.

The previous prime is 252133121081. The next prime is 252133121183. The reversal of 252133121131 is 131121331252.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 252133121131 - 211 = 252133119083 is a prime.

It is a super-2 number, since 2×2521331211312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 252133121096 and 252133121105.

It is not an unprimeable number, because it can be changed into a prime (252133127131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 106855 + ... + 718111.

It is an arithmetic number, because the mean of its divisors is an integer number (31626488920).

Almost surely, 2252133121131 is an apocalyptic number.

252133121131 is a deficient number, since it is larger than the sum of its proper divisors (878790229).

252133121131 is a wasteful number, since it uses less digits than its factorization.

252133121131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 612693.

The product of its digits is 1080, while the sum is 25.

Adding to 252133121131 its reverse (131121331252), we get a palindrome (383254452383).

The spelling of 252133121131 in words is "two hundred fifty-two billion, one hundred thirty-three million, one hundred twenty-one thousand, one hundred thirty-one".

Divisors: 1 397 1039 412483 611257 242669029 635096023 252133121131