Base | Representation |
---|---|
bin | 1110101011010011100… |
… | …1101101010111000111 |
3 | 220002211021210010212111 |
4 | 3222310321231113013 |
5 | 13112342120130210 |
6 | 311455530201451 |
7 | 24134225146225 |
oct | 3526471552707 |
9 | 802737703774 |
10 | 252143130055 |
11 | 97a2a250613 |
12 | 40a4a283287 |
13 | 1aa1409b19b |
14 | c2bd2c7b15 |
15 | 685b05088a |
hex | 3ab4e6d5c7 |
252143130055 has 8 divisors (see below), whose sum is σ = 315727049952. Its totient is φ = 192944308128.
The previous prime is 252143130049. The next prime is 252143130133. The reversal of 252143130055 is 550031341252.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 252143130055 - 23 = 252143130047 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 252143129999 and 252143130026.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1096274364 + ... + 1096274593.
It is an arithmetic number, because the mean of its divisors is an integer number (39465881244).
Almost surely, 2252143130055 is an apocalyptic number.
252143130055 is a deficient number, since it is larger than the sum of its proper divisors (63583919897).
252143130055 is a wasteful number, since it uses less digits than its factorization.
252143130055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2192548985.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 252143130055 in words is "two hundred fifty-two billion, one hundred forty-three million, one hundred thirty thousand, fifty-five".
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