Base | Representation |
---|---|
bin | 1110101011010101101… |
… | …1100011001101111011 |
3 | 220002211220110212001221 |
4 | 3222311123203031323 |
5 | 13112401403021103 |
6 | 311500444252511 |
7 | 24134363435221 |
oct | 3526533431573 |
9 | 802756425057 |
10 | 252152001403 |
11 | 97a3425a805 |
12 | 40a51241137 |
13 | 1aa15b860c3 |
14 | c2c0556b11 |
15 | 685bc041bd |
hex | 3ab56e337b |
252152001403 has 4 divisors (see below), whose sum is σ = 252244946248. Its totient is φ = 252059056560.
The previous prime is 252152001401. The next prime is 252152001463. The reversal of 252152001403 is 304100251252.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 252152001403 - 21 = 252152001401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (252152001401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46468353 + ... + 46473778.
It is an arithmetic number, because the mean of its divisors is an integer number (63061236562).
Almost surely, 2252152001403 is an apocalyptic number.
252152001403 is a deficient number, since it is larger than the sum of its proper divisors (92944845).
252152001403 is an equidigital number, since it uses as much as digits as its factorization.
252152001403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92944844.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 252152001403 its reverse (304100251252), we get a palindrome (556252252655).
The spelling of 252152001403 in words is "two hundred fifty-two billion, one hundred fifty-two million, one thousand, four hundred three".
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