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252310613341 = 2310970026667
BaseRepresentation
bin1110101011111011100…
…0100110110101011101
3220010020221221011202011
43222332320212311131
513113213004111331
6311524312031221
724141330553543
oct3527670466535
9803227834664
10252310613341
1198005844256
1240a96392511
131aa3c9abb17
14c2d7643d93
15686aad53b1
hex3abee26d5d

252310613341 has 4 divisors (see below), whose sum is σ = 263280640032. Its totient is φ = 241340586652.

The previous prime is 252310613339. The next prime is 252310613363. The reversal of 252310613341 is 143316013252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 252310613341 - 21 = 252310613339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252310613641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5485013311 + ... + 5485013356.

It is an arithmetic number, because the mean of its divisors is an integer number (65820160008).

Almost surely, 2252310613341 is an apocalyptic number.

It is an amenable number.

252310613341 is a deficient number, since it is larger than the sum of its proper divisors (10970026691).

252310613341 is a wasteful number, since it uses less digits than its factorization.

252310613341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10970026690.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 252310613341 its reverse (143316013252), we get a palindrome (395626626593).

The spelling of 252310613341 in words is "two hundred fifty-two billion, three hundred ten million, six hundred thirteen thousand, three hundred forty-one".

Divisors: 1 23 10970026667 252310613341