Base | Representation |
---|---|
bin | 1110101011111011100… |
… | …0100110110101011101 |
3 | 220010020221221011202011 |
4 | 3222332320212311131 |
5 | 13113213004111331 |
6 | 311524312031221 |
7 | 24141330553543 |
oct | 3527670466535 |
9 | 803227834664 |
10 | 252310613341 |
11 | 98005844256 |
12 | 40a96392511 |
13 | 1aa3c9abb17 |
14 | c2d7643d93 |
15 | 686aad53b1 |
hex | 3abee26d5d |
252310613341 has 4 divisors (see below), whose sum is σ = 263280640032. Its totient is φ = 241340586652.
The previous prime is 252310613339. The next prime is 252310613363. The reversal of 252310613341 is 143316013252.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 252310613341 - 21 = 252310613339 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (252310613641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5485013311 + ... + 5485013356.
It is an arithmetic number, because the mean of its divisors is an integer number (65820160008).
Almost surely, 2252310613341 is an apocalyptic number.
It is an amenable number.
252310613341 is a deficient number, since it is larger than the sum of its proper divisors (10970026691).
252310613341 is a wasteful number, since it uses less digits than its factorization.
252310613341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10970026690.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 252310613341 its reverse (143316013252), we get a palindrome (395626626593).
The spelling of 252310613341 in words is "two hundred fifty-two billion, three hundred ten million, six hundred thirteen thousand, three hundred forty-one".
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