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252340142503 = 1301193958603
BaseRepresentation
bin1110101100000010100…
…1010000000110100111
3220010100000111102010211
43223000221100012213
513113243034030003
6311531245000251
724142136551441
oct3530051200647
9803300442124
10252340142503
1198020482a19
1240aa4253087
131aa45b4a6b7
14c2db52d491
15686d4b996d
hex3ac0a501a7

252340142503 has 4 divisors (see below), whose sum is σ = 252534102408. Its totient is φ = 252146182600.

The previous prime is 252340142459. The next prime is 252340142519. The reversal of 252340142503 is 305241043252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 252340142503 - 217 = 252340011431 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252340142573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96978001 + ... + 96980602.

It is an arithmetic number, because the mean of its divisors is an integer number (63133525602).

Almost surely, 2252340142503 is an apocalyptic number.

252340142503 is a deficient number, since it is larger than the sum of its proper divisors (193959905).

252340142503 is a wasteful number, since it uses less digits than its factorization.

252340142503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 193959904.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 252340142503 its reverse (305241043252), we get a palindrome (557581185755).

The spelling of 252340142503 in words is "two hundred fifty-two billion, three hundred forty million, one hundred forty-two thousand, five hundred three".

Divisors: 1 1301 193958603 252340142503