Base | Representation |
---|---|
bin | 11110000101111… |
… | …00011001101111 |
3 | 122120222202202212 |
4 | 33002330121233 |
5 | 1004110224220 |
6 | 41014241035 |
7 | 6153422222 |
oct | 1702743157 |
9 | 576882685 |
10 | 252429935 |
11 | 11a54338a |
12 | 7065617b |
13 | 403b3734 |
14 | 2574d5b9 |
15 | 172640c5 |
hex | f0bc66f |
252429935 has 4 divisors (see below), whose sum is σ = 302915928. Its totient is φ = 201943944.
The previous prime is 252429913. The next prime is 252429943. The reversal of 252429935 is 539924252.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 252429935 - 28 = 252429679 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 252429892 and 252429901.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25242989 + ... + 25242998.
It is an arithmetic number, because the mean of its divisors is an integer number (75728982).
Almost surely, 2252429935 is an apocalyptic number.
252429935 is a deficient number, since it is larger than the sum of its proper divisors (50485993).
252429935 is an equidigital number, since it uses as much as digits as its factorization.
252429935 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50485992.
The product of its digits is 194400, while the sum is 41.
The square root of 252429935 is about 15888.0437751159. The cubic root of 252429935 is about 631.9949652099.
The spelling of 252429935 in words is "two hundred fifty-two million, four hundred twenty-nine thousand, nine hundred thirty-five".
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