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2525282807 = 5051499957
BaseRepresentation
bin1001011010000100…
…1100000111110111
320111222202122202212
42112201030013313
520132433022212
61054325324035
7116402356355
oct22641140767
96458678685
102525282807
111086502393
125a586661b
133132422a8
1419d5527d5
15eba71e22
hex9684c1f7

2525282807 has 4 divisors (see below), whose sum is σ = 2525787816. Its totient is φ = 2524777800.

The previous prime is 2525282803. The next prime is 2525282821. The reversal of 2525282807 is 7082825252.

2525282807 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2525282807 - 22 = 2525282803 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2525282803) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244928 + ... + 255029.

It is an arithmetic number, because the mean of its divisors is an integer number (631446954).

Almost surely, 22525282807 is an apocalyptic number.

2525282807 is a deficient number, since it is larger than the sum of its proper divisors (505009).

2525282807 is an equidigital number, since it uses as much as digits as its factorization.

2525282807 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 505008.

The product of its (nonzero) digits is 179200, while the sum is 41.

The square root of 2525282807 is about 50252.1920616405. The cubic root of 2525282807 is about 1361.7686776109.

The spelling of 2525282807 in words is "two billion, five hundred twenty-five million, two hundred eighty-two thousand, eight hundred seven".

Divisors: 1 5051 499957 2525282807