Base | Representation |
---|---|
bin | 1011011110111101101001… |
… | …00000011101111001010011 |
3 | 10022102011202211022002111101 |
4 | 11233132310200131321103 |
5 | 11302221413113034443 |
6 | 125413044411525231 |
7 | 5214323244010345 |
oct | 557366440357123 |
9 | 108364684262441 |
10 | 25253141143123 |
11 | 80568849110a3 |
12 | 29ba289a59817 |
13 | 1112490138b4a |
14 | 63438967d295 |
15 | 2dbd5b04584d |
hex | 16f7b481de53 |
25253141143123 has 16 divisors (see below), whose sum is σ = 25971067882080. Its totient is φ = 24544174726656.
The previous prime is 25253141143019. The next prime is 25253141143147. The reversal of 25253141143123 is 32134114135252.
It is not a de Polignac number, because 25253141143123 - 217 = 25253141012051 is a prime.
It is a super-2 number, since 2×252531411431232 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25253141143823) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 184221973 + ... + 184359001.
It is an arithmetic number, because the mean of its divisors is an integer number (1623191742630).
Almost surely, 225253141143123 is an apocalyptic number.
25253141143123 is a deficient number, since it is larger than the sum of its proper divisors (717926738957).
25253141143123 is a wasteful number, since it uses less digits than its factorization.
25253141143123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 169686.
The product of its digits is 86400, while the sum is 37.
Adding to 25253141143123 its reverse (32134114135252), we get a palindrome (57387255278375).
The spelling of 25253141143123 in words is "twenty-five trillion, two hundred fifty-three billion, one hundred forty-one million, one hundred forty-three thousand, one hundred twenty-three".
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