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25261323 = 38420441
BaseRepresentation
bin110000001011…
…1010100001011
31202112102000120
41200113110023
522431330243
62301234323
7424501113
oct140272413
952472016
1025261323
111329422a
1285629a3
135306139
1434d8043
15233ec83
hex181750b

25261323 has 4 divisors (see below), whose sum is σ = 33681768. Its totient is φ = 16840880.

The previous prime is 25261321. The next prime is 25261331. The reversal of 25261323 is 32316252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25261323 - 21 = 25261321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25261293 and 25261302.

It is not an unprimeable number, because it can be changed into a prime (25261321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4210218 + ... + 4210223.

It is an arithmetic number, because the mean of its divisors is an integer number (8420442).

Almost surely, 225261323 is an apocalyptic number.

25261323 is a deficient number, since it is larger than the sum of its proper divisors (8420445).

25261323 is an equidigital number, since it uses as much as digits as its factorization.

25261323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8420444.

The product of its digits is 2160, while the sum is 24.

The square root of 25261323 is about 5026.0643648883. The cubic root of 25261323 is about 293.4170618709.

Adding to 25261323 its reverse (32316252), we get a palindrome (57577575).

The spelling of 25261323 in words is "twenty-five million, two hundred sixty-one thousand, three hundred twenty-three".

Divisors: 1 3 8420441 25261323