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2530334111314 = 21265167055657
BaseRepresentation
bin100100110100100011101…
…010100111011001010010
322221220020100001002010211
4210310203222213121102
5312424111013030224
65214230333314334
7350545016033632
oct44644352473122
98856210032124
102530334111314
11896121705069
1234a48b9359aa
131547c0059429
148a67c6506c2
1545c46c35894
hex24d23aa7652

2530334111314 has 4 divisors (see below), whose sum is σ = 3795501166974. Its totient is φ = 1265167055656.

The previous prime is 2530334111269. The next prime is 2530334111353. The reversal of 2530334111314 is 4131114330352.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2474697095689 + 55637015625 = 1573117^2 + 235875^2 .

It is a super-4 number, since 4×25303341113144 (a number of 51 digits) contains 4444 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 632583527827 + ... + 632583527830.

Almost surely, 22530334111314 is an apocalyptic number.

2530334111314 is a deficient number, since it is larger than the sum of its proper divisors (1265167055660).

2530334111314 is a wasteful number, since it uses less digits than its factorization.

2530334111314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1265167055659.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 2530334111314 its reverse (4131114330352), we get a palindrome (6661448441666).

The spelling of 2530334111314 in words is "two trillion, five hundred thirty billion, three hundred thirty-four million, one hundred eleven thousand, three hundred fourteen".

Divisors: 1 2 1265167055657 2530334111314