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253034125143 = 3372279586713
BaseRepresentation
bin1110101110101000000…
…0100101011101010111
3220012010101100101100120
43223222000211131113
513121203214001033
6312124155243023
724165264401442
oct3535200453527
9805111311316
10253034125143
1198347192398
1241058749473
131ab26860c07
14c36577c659
1568ae39e1b3
hex3aea025757

253034125143 has 8 divisors (see below), whose sum is σ = 346497180528. Its totient is φ = 164130243264.

The previous prime is 253034125139. The next prime is 253034125147. The reversal of 253034125143 is 341521430352.

It is an interprime number because it is at equal distance from previous prime (253034125139) and next prime (253034125147).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 253034125143 - 22 = 253034125139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253034125147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1139793246 + ... + 1139793467.

It is an arithmetic number, because the mean of its divisors is an integer number (43312147566).

Almost surely, 2253034125143 is an apocalyptic number.

253034125143 is a deficient number, since it is larger than the sum of its proper divisors (93463055385).

253034125143 is a wasteful number, since it uses less digits than its factorization.

253034125143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2279586753.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 253034125143 its reverse (341521430352), we get a palindrome (594555555495).

The spelling of 253034125143 in words is "two hundred fifty-three billion, thirty-four million, one hundred twenty-five thousand, one hundred forty-three".

Divisors: 1 3 37 111 2279586713 6838760139 84344708381 253034125143