Base | Representation |
---|---|
bin | 100100110100101000110… |
… | …111011000110010100101 |
3 | 22221220110102012000212120 |
4 | 210310220313120302211 |
5 | 312424300331023240 |
6 | 5214243131140153 |
7 | 350550125356560 |
oct | 44645067306245 |
9 | 8856412160776 |
10 | 2530421345445 |
11 | 896166977394 |
12 | 34a4b4ba4659 |
13 | 154805150466 |
14 | 8a68a07b4d7 |
15 | 45c4e717ad0 |
hex | 24d28dd8ca5 |
2530421345445 has 16 divisors (see below), whose sum is σ = 4627056174720. Its totient is φ = 1156764043584.
The previous prime is 2530421345443. The next prime is 2530421345467. The reversal of 2530421345445 is 5445431240352.
It is not a de Polignac number, because 2530421345445 - 21 = 2530421345443 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2530421345397 and 2530421345406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2530421345443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12049625350 + ... + 12049625559.
It is an arithmetic number, because the mean of its divisors is an integer number (289191010920).
Almost surely, 22530421345445 is an apocalyptic number.
It is an amenable number.
2530421345445 is a deficient number, since it is larger than the sum of its proper divisors (2096634829275).
2530421345445 is a wasteful number, since it uses less digits than its factorization.
2530421345445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24099250924.
The product of its (nonzero) digits is 1152000, while the sum is 42.
Adding to 2530421345445 its reverse (5445431240352), we get a palindrome (7975852585797).
The spelling of 2530421345445 in words is "two trillion, five hundred thirty billion, four hundred twenty-one million, three hundred forty-five thousand, four hundred forty-five".
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