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253053514039999 = 793203209038481
BaseRepresentation
bin111001100010011010011100…
…110100000100001010111111
31020011222200100111011111102211
4321202122130310010022333
5231132012044043234444
62254111102434001251
7104205340660112251
oct7142323464041277
91204880314144384
10253053514039999
11736a3435647452
122446b571a16227
13ab27ac82c577a
14466bbd9429cd1
151e3c781569c34
hexe6269cd042bf

253053514039999 has 4 divisors (see below), whose sum is σ = 256256723078560. Its totient is φ = 249850305001440.

The previous prime is 253053514039967. The next prime is 253053514040003. The reversal of 253053514039999 is 999930415350352.

253053514039999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 253053514039999 - 25 = 253053514039967 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253053514039499) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1601604519162 + ... + 1601604519319.

It is an arithmetic number, because the mean of its divisors is an integer number (64064180769640).

Almost surely, 2253053514039999 is an apocalyptic number.

253053514039999 is a deficient number, since it is larger than the sum of its proper divisors (3203209038561).

253053514039999 is an equidigital number, since it uses as much as digits as its factorization.

253053514039999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3203209038560.

The product of its (nonzero) digits is 177147000, while the sum is 67.

The spelling of 253053514039999 in words is "two hundred fifty-three trillion, fifty-three billion, five hundred fourteen million, thirty-nine thousand, nine hundred ninety-nine".

Divisors: 1 79 3203209038481 253053514039999