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253083080501 = 416172758061
BaseRepresentation
bin1110101110110011101…
…1010101011100110101
3220012020210110120110222
43223230323111130311
513121303232034001
6312133104424125
724166430455436
oct3535473253465
9805223416428
10253083080501
119837188a269
1241071018045
131ab33a41994
14c36c08348d
1568b381e61b
hex3aeced5735

253083080501 has 4 divisors (see below), whose sum is σ = 259255838604. Its totient is φ = 246910322400.

The previous prime is 253083080461. The next prime is 253083080519. The reversal of 253083080501 is 105080380352.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 60208399876 + 192874680625 = 245374^2 + 439175^2 .

It is a cyclic number.

It is not a de Polignac number, because 253083080501 - 234 = 235903211317 is a prime.

It is a super-3 number, since 3×2530830805013 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253083080521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3086378990 + ... + 3086379071.

It is an arithmetic number, because the mean of its divisors is an integer number (64813959651).

Almost surely, 2253083080501 is an apocalyptic number.

It is an amenable number.

253083080501 is a deficient number, since it is larger than the sum of its proper divisors (6172758103).

253083080501 is an equidigital number, since it uses as much as digits as its factorization.

253083080501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6172758102.

The product of its (nonzero) digits is 28800, while the sum is 35.

The spelling of 253083080501 in words is "two hundred fifty-three billion, eighty-three million, eighty thousand, five hundred one".

Divisors: 1 41 6172758061 253083080501