2531314042301 has 4 divisors (see below), whose sum is σ = 2761433500704. Its totient is φ = 2301194583900.

The previous prime is 2531314042247. The next prime is 2531314042303. The reversal of 2531314042301 is 1032404131352.

2531314042301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2531314042301 - 2¹⁴ = 2531314025917 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2531314042303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115059729185 + ... + 115059729206.

It is an arithmetic number, because the mean of its divisors is an integer number (690358375176).

Almost surely, 2^{2531314042301} is an apocalyptic number.

It is an amenable number.

2531314042301 is a deficient number, since it is larger than the sum of its proper divisors (230119458403).

2531314042301 is a wasteful number, since it uses less digits than its factorization.

2531314042301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 230119458402.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 2531314042301 its reverse (1032404131352), we get a palindrome (3563718173653).

The spelling of 2531314042301 in words is "two trillion, five hundred thirty-one billion, three hundred fourteen million, forty-two thousand, three hundred one".