25314139797 has 4 divisors (see below), whose sum is σ = 33752186400. Its totient is φ = 16876093196.

The previous prime is 25314139777. The next prime is 25314139801. The reversal of 25314139797 is 79793141352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25314139797 - 2¹⁵ = 25314107029 is a prime.

It is a super-3 number, since 3×25314139797³ (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25314139757) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4219023297 + ... + 4219023302.

It is an arithmetic number, because the mean of its divisors is an integer number (8438046600).

Almost surely, 2^25314139797 is an apocalyptic number.

It is an amenable number.

25314139797 is a deficient number, since it is larger than the sum of its proper divisors (8438046603).

25314139797 is an equidigital number, since it uses as much as digits as its factorization.

25314139797 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8438046602.

The product of its digits is 1428840, while the sum is 51.

The spelling of 25314139797 in words is "twenty-five billion, three hundred fourteen million, one hundred thirty-nine thousand, seven hundred ninety-seven".