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2531414123113 = 20999739123833
BaseRepresentation
bin100100110101100100000…
…010100010001001101001
322222000000121021100210211
4210311210002202021221
5312433314003414423
65214525433541121
7350613542010241
oct44654402421151
98860017240724
102531414123113
118966263079a7
1234a7315747a1
13154932a2c175
148a741c68b21
1545cab96e10d
hex24d640a2269

2531414123113 has 8 divisors (see below), whose sum is σ = 2532900636000. Its totient is φ = 2529927881568.

The previous prime is 2531414123101. The next prime is 2531414123177. The reversal of 2531414123113 is 3113214141352.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2531414123113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2531414121113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20380245 + ... + 20504077.

It is an arithmetic number, because the mean of its divisors is an integer number (316612579500).

Almost surely, 22531414123113 is an apocalyptic number.

It is an amenable number.

2531414123113 is a deficient number, since it is larger than the sum of its proper divisors (1486512887).

2531414123113 is a wasteful number, since it uses less digits than its factorization.

2531414123113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135671.

The product of its digits is 8640, while the sum is 31.

Adding to 2531414123113 its reverse (3113214141352), we get a palindrome (5644628264465).

The spelling of 2531414123113 in words is "two trillion, five hundred thirty-one billion, four hundred fourteen million, one hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 2099 9739 123833 20442161 259925467 1206009587 2531414123113