Base | Representation |
---|---|
bin | 1110101111000100011… |
… | …1010100111101111001 |
3 | 220012102200122202221120 |
4 | 3223301013110331321 |
5 | 13121424223124423 |
6 | 312144054255453 |
7 | 24201242553522 |
oct | 3536107247571 |
9 | 805380582846 |
10 | 253153333113 |
11 | 983a850307a |
12 | 41090657589 |
13 | 1ab4546b485 |
14 | c37752d849 |
15 | 68b9a99ee3 |
hex | 3af11d4f79 |
253153333113 has 32 divisors (see below), whose sum is σ = 344657203200. Its totient is φ = 165245875200.
The previous prime is 253153333049. The next prime is 253153333117. The reversal of 253153333113 is 311333351352.
It is not a de Polignac number, because 253153333113 - 26 = 253153333049 is a prime.
It is a super-2 number, since 2×2531533331132 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (253153333117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19287193 + ... + 19300313.
It is an arithmetic number, because the mean of its divisors is an integer number (10770537600).
Almost surely, 2253153333113 is an apocalyptic number.
It is an amenable number.
253153333113 is a deficient number, since it is larger than the sum of its proper divisors (91503870087).
253153333113 is a wasteful number, since it uses less digits than its factorization.
253153333113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13813.
The product of its digits is 36450, while the sum is 33.
Adding to 253153333113 its reverse (311333351352), we get a palindrome (564486684465).
The spelling of 253153333113 in words is "two hundred fifty-three billion, one hundred fifty-three million, three hundred thirty-three thousand, one hundred thirteen".
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