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253315360166455 = 52314629150573673
BaseRepresentation
bin111001100110001110010100…
…000011110001001000110111
31020012220201012222211221002101
4321212032110003301020313
5231200304324200311310
62254431245301122531
7104233300525343656
oct7146162403611067
91205821188757071
10253315360166455
1173794493994854
12244b22696b9447
13ab466c7692132
14467a75924319d
151e444a935c43a
hexe663940f1237

253315360166455 has 16 divisors (see below), whose sum is σ = 317216570489280. Its totient is φ = 193828067313408.

The previous prime is 253315360166443. The next prime is 253315360166471. The reversal of 253315360166455 is 554661063513352.

It is a de Polignac number, because none of the positive numbers 2k-253315360166455 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253315360166396 and 253315360166405.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73604502 + ... + 76969171.

It is an arithmetic number, because the mean of its divisors is an integer number (19826035655580).

Almost surely, 2253315360166455 is an apocalyptic number.

253315360166455 is a deficient number, since it is larger than the sum of its proper divisors (63901210322825).

253315360166455 is a wasteful number, since it uses less digits than its factorization.

253315360166455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150588330.

The product of its (nonzero) digits is 29160000, while the sum is 55.

The spelling of 253315360166455 in words is "two hundred fifty-three trillion, three hundred fifteen billion, three hundred sixty million, one hundred sixty-six thousand, four hundred fifty-five".

Divisors: 1 5 23 115 14629 73145 336467 1682335 150573673 752868365 3463194479 17315972395 2202742262317 11013711311585 50663072033291 253315360166455