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253400554015121 = 268499437988529
BaseRepresentation
bin111001100111011101101010…
…000000100000100110010001
31020020012212010022002212000202
4321213131222000200212101
5231203203313311440441
62254534335113024545
7104242404645200342
oct7147355200404621
91206185108085022
10253400554015121
117381763166a247
12245068849b5155
13ab51753867c86
14468091bb000c9
151e467e37c419b
hexe6776a020991

253400554015121 has 4 divisors (see below), whose sum is σ = 253409992030500. Its totient is φ = 253391115999744.

The previous prime is 253400554015109. The next prime is 253400554015123. The reversal of 253400554015121 is 121510455004352.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 185633676315025 + 67766877700096 = 13624745^2 + 8232064^2 .

It is a cyclic number.

It is not a de Polignac number, because 253400554015121 - 226 = 253400486906257 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (253400554015123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4718967416 + ... + 4719021113.

It is an arithmetic number, because the mean of its divisors is an integer number (63352498007625).

Almost surely, 2253400554015121 is an apocalyptic number.

It is an amenable number.

253400554015121 is a deficient number, since it is larger than the sum of its proper divisors (9438015379).

253400554015121 is an equidigital number, since it uses as much as digits as its factorization.

253400554015121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9438015378.

The product of its (nonzero) digits is 120000, while the sum is 38.

The spelling of 253400554015121 in words is "two hundred fifty-three trillion, four hundred billion, five hundred fifty-four million, fifteen thousand, one hundred twenty-one".

Divisors: 1 26849 9437988529 253400554015121