253421535303311 has 4 divisors (see below), whose sum is σ = 253439571153624. Its totient is φ = 253403499453000.

The previous prime is 253421535303241. The next prime is 253421535303331. The reversal of 253421535303311 is 113303535124352.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-253421535303311 is a prime.

It is a super-3 number, since 3×253421535303311³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253421535303331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9017904080 + ... + 9017932181.

It is an arithmetic number, because the mean of its divisors is an integer number (63359892788406).

Almost surely, 2^{253421535303311} is an apocalyptic number.

253421535303311 is a deficient number, since it is larger than the sum of its proper divisors (18035850313).

253421535303311 is a wasteful number, since it uses less digits than its factorization.

253421535303311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18035850312.

The product of its (nonzero) digits is 486000, while the sum is 41.

The spelling of 253421535303311 in words is "two hundred fifty-three trillion, four hundred twenty-one billion, five hundred thirty-five million, three hundred three thousand, three hundred eleven".