Base | Representation |
---|---|
bin | 1110110000000110100… |
… | …1101000010110001011 |
3 | 220020011000200120020200 |
4 | 3230001221220112023 |
5 | 13123011233321333 |
6 | 312231404423243 |
7 | 24211151631651 |
oct | 3540151502613 |
9 | 806130616220 |
10 | 253430760843 |
11 | 9853006a697 |
12 | 41149547b23 |
13 | 1ab8aa950b0 |
14 | c3a2308dd1 |
15 | 68d40eac13 |
hex | 3b01a6858b |
253430760843 has 48 divisors (see below), whose sum is σ = 415162325760. Its totient is φ = 147682180800.
The previous prime is 253430760841. The next prime is 253430760887. The reversal of 253430760843 is 348067034352.
253430760843 is a `hidden beast` number, since 2 + 5 + 3 + 4 + 30 + 7 + 608 + 4 + 3 = 666.
It is not a de Polignac number, because 253430760843 - 21 = 253430760841 is a prime.
It is not an unprimeable number, because it can be changed into a prime (253430760841) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5112688 + ... + 5162018.
It is an arithmetic number, because the mean of its divisors is an integer number (8649215120).
Almost surely, 2253430760843 is an apocalyptic number.
253430760843 is a deficient number, since it is larger than the sum of its proper divisors (161731564917).
253430760843 is a wasteful number, since it uses less digits than its factorization.
253430760843 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51680 (or 51677 counting only the distinct ones).
The product of its (nonzero) digits is 1451520, while the sum is 45.
The spelling of 253430760843 in words is "two hundred fifty-three billion, four hundred thirty million, seven hundred sixty thousand, eight hundred forty-three".
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