253433313101341 has 4 divisors (see below), whose sum is σ = 253478788311132. Its totient is φ = 253387837891552.

The previous prime is 253433313101321. The next prime is 253433313101347. The reversal of 253433313101341 is 143101313334352.

253433313101341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 137921418560025 + 115511894541316 = 11743995^2 + 10747646^2 .

It is a cyclic number.

It is not a de Polignac number, because 253433313101341 - 2⁹ = 253433313100829 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 253433313101341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253433313101347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22737596536 + ... + 22737607681.

It is an arithmetic number, because the mean of its divisors is an integer number (63369697077783).

Almost surely, 2^{253433313101341} is an apocalyptic number.

It is an amenable number.

253433313101341 is a deficient number, since it is larger than the sum of its proper divisors (45475209791).

253433313101341 is an equidigital number, since it uses as much as digits as its factorization.

253433313101341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45475209790.

The product of its (nonzero) digits is 116640, while the sum is 37.

Adding to 253433313101341 its reverse (143101313334352), we get a palindrome (396534626435693).

The spelling of 253433313101341 in words is "two hundred fifty-three trillion, four hundred thirty-three billion, three hundred thirteen million, one hundred one thousand, three hundred forty-one".