Base | Representation |
---|---|
bin | 111001100111111101000101… |
… | …011111100100110001010011 |
3 | 1020020100002020012021102110200 |
4 | 321213331011133210301103 |
5 | 231204231422042440201 |
6 | 2255002035523030243 |
7 | 104245011145054563 |
oct | 7147750537446123 |
9 | 1206302205242420 |
10 | 253434301140051 |
11 | 7382a979a7a739 |
12 | 2451132280b383 |
13 | ab549a1343555 |
14 | 46823dda74da3 |
15 | 1e4761b372386 |
hex | e67f457e4c53 |
253434301140051 has 24 divisors (see below), whose sum is σ = 371536672525824. Its totient is φ = 166433952841200.
The previous prime is 253434301139989. The next prime is 253434301140079. The reversal of 253434301140051 is 150041103434352.
253434301140051 is a `hidden beast` number, since 2 + 5 + 3 + 434 + 30 + 1 + 140 + 0 + 51 = 666.
It is not a de Polignac number, because 253434301140051 - 214 = 253434301123667 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 253434301139988 and 253434301140015.
It is not an unprimeable number, because it can be changed into a prime (253434301147051) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 381950626 + ... + 382613576.
It is an arithmetic number, because the mean of its divisors is an integer number (15480694688576).
Almost surely, 2253434301140051 is an apocalyptic number.
253434301140051 is a deficient number, since it is larger than the sum of its proper divisors (118102371385773).
253434301140051 is a wasteful number, since it uses less digits than its factorization.
253434301140051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1296991 (or 1296988 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
The spelling of 253434301140051 in words is "two hundred fifty-three trillion, four hundred thirty-four billion, three hundred one million, one hundred forty thousand, fifty-one".
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