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25345013413 = 216111172783
BaseRepresentation
bin10111100110101011…
…100011011010100101
32102102100010002020111
4113212223203122211
5403401310412123
615350543333021
71555034026246
oct274653433245
972370102214
1025345013413
11a826665785
124ab3bb1171
13250bb64a75
141326116ccd
159d512390d
hex5e6ae36a5

25345013413 has 4 divisors (see below), whose sum is σ = 25346207808. Its totient is φ = 25343819020.

The previous prime is 25345013411. The next prime is 25345013443. The reversal of 25345013413 is 31431054352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25345013413 - 21 = 25345013411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25345013411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 564781 + ... + 608002.

It is an arithmetic number, because the mean of its divisors is an integer number (6336551952).

Almost surely, 225345013413 is an apocalyptic number.

It is an amenable number.

25345013413 is a deficient number, since it is larger than the sum of its proper divisors (1194395).

25345013413 is a wasteful number, since it uses less digits than its factorization.

25345013413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1194394.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 25345013413 its reverse (31431054352), we get a palindrome (56776067765).

The spelling of 25345013413 in words is "twenty-five billion, three hundred forty-five million, thirteen thousand, four hundred thirteen".

Divisors: 1 21611 1172783 25345013413