253451430231541 has 4 divisors (see below), whose sum is σ = 253550550856012. Its totient is φ = 253352309607072.

The previous prime is 253451430231511. The next prime is 253451430231589. The reversal of 253451430231541 is 145132034154352.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 95594695780516 + 157856734451025 = 9777254^2 + 12564105^2 .

It is a cyclic number.

It is not a de Polignac number, because 253451430231541 - 2¹⁷ = 253451430100469 is a prime.

It is a super-3 number, since 3×253451430231541³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253451430231511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49560308400 + ... + 49560313513.

It is an arithmetic number, because the mean of its divisors is an integer number (63387637714003).

Almost surely, 2^{253451430231541} is an apocalyptic number.

It is an amenable number.

253451430231541 is a deficient number, since it is larger than the sum of its proper divisors (99120624471).

253451430231541 is an equidigital number, since it uses as much as digits as its factorization.

253451430231541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99120624470.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 253451430231541 its reverse (145132034154352), we get a palindrome (398583464385893).

The spelling of 253451430231541 in words is "two hundred fifty-three trillion, four hundred fifty-one billion, four hundred thirty million, two hundred thirty-one thousand, five hundred forty-one".