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253453111042 = 2126726555521
BaseRepresentation
bin1110110000001011111…
…0111000111100000010
3220020012120202001221211
43230002332320330002
513123032444023132
6312233523440334
724211542616615
oct3540276707402
9806176661854
10253453111042
119854174572a
1241154b260aa
131ab925bc171
14c3a528617c
1568d6063147
hex3b02fb8f02

253453111042 has 4 divisors (see below), whose sum is σ = 380179666566. Its totient is φ = 126726555520.

The previous prime is 253453111031. The next prime is 253453111069. The reversal of 253453111042 is 240111354352.

253453111042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 233280306081 + 20172804961 = 482991^2 + 142031^2 .

It is a junction number, because it is equal to n+sod(n) for n = 253453110995 and 253453111013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63363277759 + ... + 63363277762.

Almost surely, 2253453111042 is an apocalyptic number.

253453111042 is a deficient number, since it is larger than the sum of its proper divisors (126726555524).

253453111042 is a wasteful number, since it uses less digits than its factorization.

253453111042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 126726555523.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 253453111042 its reverse (240111354352), we get a palindrome (493564465394).

The spelling of 253453111042 in words is "two hundred fifty-three billion, four hundred fifty-three million, one hundred eleven thousand, forty-two".

Divisors: 1 2 126726555521 253453111042