Base | Representation |
---|---|
bin | 1110110000011101001… |
… | …0101010010101111111 |
3 | 220020101121202212220000 |
4 | 3230013102222111333 |
5 | 13123210000344012 |
6 | 312245025125343 |
7 | 24213411240432 |
oct | 3540722522577 |
9 | 806347685800 |
10 | 253525403007 |
11 | 98579531758 |
12 | 41175189853 |
13 | 1aba4580c86 |
14 | c3b0b03819 |
15 | 68dc592ddc |
hex | 3b074aa57f |
253525403007 has 20 divisors (see below), whose sum is σ = 395189358960. Its totient is φ = 161668371744.
The previous prime is 253525402993. The next prime is 253525403069. The reversal of 253525403007 is 700304525352.
253525403007 is a `hidden beast` number, since 253 + 52 + 54 + 0 + 300 + 7 = 666.
It is not a de Polignac number, because 253525403007 - 28 = 253525402751 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (253525403407) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 68040382 + ... + 68044107.
It is an arithmetic number, because the mean of its divisors is an integer number (19759467948).
Almost surely, 2253525403007 is an apocalyptic number.
253525403007 is a gapful number since it is divisible by the number (27) formed by its first and last digit.
253525403007 is a deficient number, since it is larger than the sum of its proper divisors (141663955953).
253525403007 is a wasteful number, since it uses less digits than its factorization.
253525403007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136084524 (or 136084515 counting only the distinct ones).
The product of its (nonzero) digits is 126000, while the sum is 36.
Adding to 253525403007 its reverse (700304525352), we get a palindrome (953829928359).
The spelling of 253525403007 in words is "two hundred fifty-three billion, five hundred twenty-five million, four hundred three thousand, seven".
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