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253532000113 = 783436371773
BaseRepresentation
bin1110110000011110101…
…1110100111101110001
3220020102002012001102021
43230013223310331301
513123213143000423
6312245422351441
724213521305120
oct3540753647561
9806362161367
10253532000113
1198582228207
124117742b581
131aba5a509a2
14c3b193dab7
1568dce4795d
hex3b07af4f71

253532000113 has 8 divisors (see below), whose sum is σ = 293241832128. Its totient is φ = 214694911824.

The previous prime is 253532000093. The next prime is 253532000119. The reversal of 253532000113 is 311000235352.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 253532000113 - 221 = 253529902961 is a prime.

It is not an unprimeable number, because it can be changed into a prime (253532000119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 218185306 + ... + 218186467.

It is an arithmetic number, because the mean of its divisors is an integer number (36655229016).

Almost surely, 2253532000113 is an apocalyptic number.

It is an amenable number.

253532000113 is a deficient number, since it is larger than the sum of its proper divisors (39709832015).

253532000113 is an equidigital number, since it uses as much as digits as its factorization.

253532000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 436371863.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 253532000113 its reverse (311000235352), we get a palindrome (564532235465).

The spelling of 253532000113 in words is "two hundred fifty-three billion, five hundred thirty-two million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 7 83 581 436371773 3054602411 36218857159 253532000113