253543300113 has 4 divisors (see below), whose sum is σ = 338057733488. Its totient is φ = 169028866740.

The previous prime is 253543300111. The next prime is 253543300133. The reversal of 253543300113 is 311003345352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 253543300113 - 2¹ = 253543300111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (253543300111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42257216683 + ... + 42257216688.

It is an arithmetic number, because the mean of its divisors is an integer number (84514433372).

Almost surely, 2^253543300113 is an apocalyptic number.

It is an amenable number.

253543300113 is a deficient number, since it is larger than the sum of its proper divisors (84514433375).

253543300113 is an equidigital number, since it uses as much as digits as its factorization.

253543300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84514433374.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 253543300113 its reverse (311003345352), we get a palindrome (564546645465).

The spelling of 253543300113 in words is "two hundred fifty-three billion, five hundred forty-three million, three hundred thousand, one hundred thirteen".