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253734006317 = 1123066727847
BaseRepresentation
bin1110110001001110111…
…0011010111000101101
3220020221011022000211112
43230103232122320231
513124121401200232
6312321440201405
724221523316361
oct3542356327055
9806834260745
10253734006317
1198676260490
1241213009265
131ac0885b19c
14c3d06c52a1
156900a4b4b2
hex3b13b9ae2d

253734006317 has 4 divisors (see below), whose sum is σ = 276800734176. Its totient is φ = 230667278460.

The previous prime is 253734006289. The next prime is 253734006367. The reversal of 253734006317 is 713600437352.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 253734006317 - 214 = 253733989933 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253734006367) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11533363913 + ... + 11533363934.

It is an arithmetic number, because the mean of its divisors is an integer number (69200183544).

Almost surely, 2253734006317 is an apocalyptic number.

It is an amenable number.

253734006317 is a deficient number, since it is larger than the sum of its proper divisors (23066727859).

253734006317 is a wasteful number, since it uses less digits than its factorization.

253734006317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23066727858.

The product of its (nonzero) digits is 317520, while the sum is 41.

The spelling of 253734006317 in words is "two hundred fifty-three billion, seven hundred thirty-four million, six thousand, three hundred seventeen".

Divisors: 1 11 23066727847 253734006317