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253954043291 = 1319534926407
BaseRepresentation
bin1110110010000011010…
…1110010110110011011
3220021111111100001211002
43230200311302312123
513130044213341131
6312355340255215
724230134515524
oct3544065626633
9807444301732
10253954043291
1198779489523
124127484150b
131ac4230c690
14c411a0184b
1569150126cb
hex3b20d72d9b

253954043291 has 4 divisors (see below), whose sum is σ = 273488969712. Its totient is φ = 234419116872.

The previous prime is 253954043279. The next prime is 253954043309. The reversal of 253954043291 is 192340459352.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-253954043291 is a prime.

It is a super-2 number, since 2×2539540432912 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (253954043251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9767463191 + ... + 9767463216.

It is an arithmetic number, because the mean of its divisors is an integer number (68372242428).

Almost surely, 2253954043291 is an apocalyptic number.

253954043291 is a deficient number, since it is larger than the sum of its proper divisors (19534926421).

253954043291 is a wasteful number, since it uses less digits than its factorization.

253954043291 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19534926420.

The product of its (nonzero) digits is 1166400, while the sum is 47.

The spelling of 253954043291 in words is "two hundred fifty-three billion, nine hundred fifty-four million, forty-three thousand, two hundred ninety-one".

Divisors: 1 13 19534926407 253954043291