254002151113 has 4 divisors (see below), whose sum is σ = 254003212240. Its totient is φ = 254001089988.

The previous prime is 254002151099. The next prime is 254002151159. The reversal of 254002151113 is 311151200452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-254002151113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (254002101113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16558 + ... + 712936.

It is an arithmetic number, because the mean of its divisors is an integer number (63500803060).

Almost surely, 2^254002151113 is an apocalyptic number.

It is an amenable number.

254002151113 is a deficient number, since it is larger than the sum of its proper divisors (1061127).

254002151113 is an equidigital number, since it uses as much as digits as its factorization.

254002151113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1061126.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 254002151113 its reverse (311151200452), we get a palindrome (565153351565).

The spelling of 254002151113 in words is "two hundred fifty-four billion, two million, one hundred fifty-one thousand, one hundred thirteen".