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2540051403 = 31137492777
BaseRepresentation
bin1001011101100110…
…0001101111001011
320120000112222110220
42113121201233023
520200223121103
61100014041123
7116642036451
oct22731415713
96500488426
102540051403
11109387a23a
125aa7a91a3
133163134c6
141a14b89d1
15ecedcc53
hex97661bcb

2540051403 has 8 divisors (see below), whose sum is σ = 3416706768. Its totient is φ = 1678381824.

The previous prime is 2540051401. The next prime is 2540051411. The reversal of 2540051403 is 3041500452.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2540051403 - 21 = 2540051401 is a prime.

It is a super-2 number, since 2×25400514032 = 12903722259764536818, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2540051401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3746050 + ... + 3746727.

It is an arithmetic number, because the mean of its divisors is an integer number (427088346).

Almost surely, 22540051403 is an apocalyptic number.

2540051403 is a deficient number, since it is larger than the sum of its proper divisors (876655365).

2540051403 is a wasteful number, since it uses less digits than its factorization.

2540051403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7492893.

The product of its (nonzero) digits is 2400, while the sum is 24.

The square root of 2540051403 is about 50398.9226372945. The cubic root of 2540051403 is about 1364.4181937314.

Adding to 2540051403 its reverse (3041500452), we get a palindrome (5581551855).

The spelling of 2540051403 in words is "two billion, five hundred forty million, fifty-one thousand, four hundred three".

Divisors: 1 3 113 339 7492777 22478331 846683801 2540051403