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2540100055 = 5719370627
BaseRepresentation
bin1001011101100110…
…1101100111010111
320120000122110012211
42113121231213113
520200231200210
61100015054251
7116642331343
oct22731554727
96500573184
102540100055
111093902849
125aa811387
1331632c6ac
141a14cc623
15eceec38a
hex9766d9d7

2540100055 has 8 divisors (see below), whose sum is σ = 3048586992. Its totient is φ = 2031768768.

The previous prime is 2540099983. The next prime is 2540100083. The reversal of 2540100055 is 5500010452.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2540100055 - 27 = 2540099927 is a prime.

It is a super-2 number, since 2×25401000552 = 12904216578822006050, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2540099999 and 2540100035.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 652 + ... + 71278.

It is an arithmetic number, because the mean of its divisors is an integer number (381073374).

Almost surely, 22540100055 is an apocalyptic number.

2540100055 is a deficient number, since it is larger than the sum of its proper divisors (508486937).

2540100055 is an equidigital number, since it uses as much as digits as its factorization.

2540100055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77825.

The product of its (nonzero) digits is 1000, while the sum is 22.

The square root of 2540100055 is about 50399.4053040311. The cubic root of 2540100055 is about 1364.4269050052.

The spelling of 2540100055 in words is "two billion, five hundred forty million, one hundred thousand, fifty-five".

Divisors: 1 5 7193 35965 70627 353135 508020011 2540100055