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2540131311121 = 4751353461817
BaseRepresentation
bin100100111101101011100…
…111111101111000010001
322222211112010012101200221
4210331223213331320101
5313104142103423441
65222530433313041
7351342551616445
oct44755347757021
98884463171627
102540131311121
1189a2999a4308
12350364a05781
131556c1a1bb91
148ad2b8a2825
154611bdd48d1
hex24f6b9fde11

2540131311121 has 4 divisors (see below), whose sum is σ = 2540184820452. Its totient is φ = 2540077801792.

The previous prime is 2540131311119. The next prime is 2540131311139. The reversal of 2540131311121 is 1211131310452.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1154894115600 + 1385237195521 = 1074660^2 + 1176961^2 .

It is a cyclic number.

It is not a de Polignac number, because 2540131311121 - 21 = 2540131311119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2540131311721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26683396 + ... + 26778421.

It is an arithmetic number, because the mean of its divisors is an integer number (635046205113).

Almost surely, 22540131311121 is an apocalyptic number.

It is an amenable number.

2540131311121 is a deficient number, since it is larger than the sum of its proper divisors (53509331).

2540131311121 is an equidigital number, since it uses as much as digits as its factorization.

2540131311121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53509330.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 2540131311121 its reverse (1211131310452), we get a palindrome (3751262621573).

The spelling of 2540131311121 in words is "two trillion, five hundred forty billion, one hundred thirty-one million, three hundred eleven thousand, one hundred twenty-one".

Divisors: 1 47513 53461817 2540131311121